kthvalue consistency with sort in the presence of NaN (#17824)
Summary:
This PR causes kthvalue to be consistent with sort
(i.e. treat NaN as larger than any number), so that
`a.kthvalue(n) == a.sort()[n - 1]`.
One drawback is that median with a NaN argument does not return NaN,
which is a deviation from NumPy.
Thank you, ngimel, for raising this.
Pull Request resolved: https://github.com/pytorch/pytorch/pull/17824
Differential Revision: D14410092
Pulled By: ezyang
fbshipit-source-id: bdec2d8272dc4c65bcf2f9b8995e237774c44c02
